According to the line of best fit, in 1995 there were 20 coyotes in the park. In 2000, there were 140 coyotes in the park. This is an increase of 120 coyotes over a period of 5 years, so ​\( \frac{120}{5} \)​= an average increase of 24 coyotes per year, which is (B).

The median number of coyotes in the park in 1995 was 20, and the median number of coyotes in the park in 1996 was 60. (Be careful to RTFQ: the question wants median, NOT line of best fit!) In order to calculate the percent increase, it is necessary to use the percent change formula: ​\( \frac{difference}{original} \)​× 100. The calculation here will be ​\( \frac{60-20}{20} \)​× 100 = ​\( \frac{40}{20} \)​× 100 = 2 × 100 = 200%, which is (D).

Start with the easier equation and use Process of Elimination. The easier equation is related to the total number of shirts and pants, s + p, sold on a regular day. The question states that on a regular day Bailey’s sells \( \frac{2}{3} \)the number of pants and shirts sold during a sale. \( \frac{2}{3} \)(60) = 40. Therefore, one of the equations in the correct answer should be s + p = 40. Eliminate (C) and (D) since neither of these answers include this equation. The other equation is related to themoney Bailey’s earns on a regular day. According to the question, Bailey’s earns a total of $1,875 on a regular day, so the equation must equal $1,875. Eliminate (B) because the total in the money equation is incorrect. The correct answer is (A).

There are a few different ways to approach this question. In any approach, the best first step is to figure out how much income Bryan earned during the two-week period without the commission. Since he worked an average of 35 hours per week for two weeks, he worked a total of 70 hours. At a rate of $10.00 per hour base pay, this would add up to $700.00 (70 × 10 = 700). Since Bryan’s earnings were actually $850.00, that means he must have earned $150.00 of commission (850 – 700 = 150). At this point, you can calculate the percent commission algebraically or simply work backwards from the answers. Algebraically, you know that $150.00 is equal to a certain percent of $5,000.00 in sales, which can be represented as follows: 150 = \( \frac{x}{100} \)(5,000). Solve for x, and you get 3, which is (C). If instead you wish to work backwards from the answers, you can take the answers and calculate what 1%, 2%, etc. of $5,000.00 would be, and then add that back to $700.00 to see which choice matches your target of $850.00: (C).

Start with the easiest piece of information first, and use Process of Elimination. Given that h is the number of hours spent hiking and d is the number of hours driving, the total number of hours Lennon spends in the park can be calculated as h + d. The question states that Lennon has up to 6 hours to spend in the park-“up to” means ≤. So, h + d ≤ 6. Eliminate (B), (C), and (D). The correct answer is (A).